0.5(2t^2-20)=5

Solution for 0.5(2t^2-20)=5 equation:

Simplifying
0.5(2t2 + -20) = 5

Reorder the terms:
0.5(-20 + 2t2) = 5
(-20 * 0.5 + 2t2 * 0.5) = 5
(-10 + 1t2) = 5

Solving
-10 + 1t2 = 5

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 1t2 = 5 + 10

Combine like terms: -10 + 10 = 0
0 + 1t2 = 5 + 10
1t2 = 5 + 10

Combine like terms: 5 + 10 = 15
1t2 = 15

Divide each side by '1'.
t2 = 15

Simplifying
t2 = 15

Take the square root of each side:
t = {-3.872983346, 3.872983346}